DotNet Visual C: I create a operator + declared in C# to be used in C++

• olafbaeyens / 206 / Wed, 03 Mar 2010 04:18:00 GMT / Comments (3)
• I create a operator + in C#

  public static HistogramBuffer operator+(HistogramBuffer
  aHistogramBuffer1, HistogramBuffer aHistogramBuffer2) {
  HistogramBuffer Tmp=new HistogramBuffer(aHistogramBuffer1);
  for (int iX=0; iX<Tmp.NrOfValues; iX++) {
  Tmp[iX]=Tmp[iX]+aHistogramBuffer2[iX];
  }
  return Tmp;
  }

  Now in C# I can do this:

  HistogramBuffer Test1=new HistogramBuffer();
  HistogramBuffer Test2=new HistogramBuffer();

  Test2=Test2+Test1;

  But if I do this In C++

  HistogramBuffer __gc *Test1=__gc new HistogramBuffer();
  HistogramBuffer __gc *Test2=__gc new HistogramBuffer();

  Test2=Test2+Test1;

  Then I get this error: "error C2845: '+' : cannot perform pointer arithmetic
  on __gc pointer...."
  Any idea how to fix this?

  --
  http://www.skyscan.be
• Keywords:

  create, operator, declared, c#, used, c++, dotnet, visual, .net

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• 1. 
     --
     cody

     Freeware Tools, Games and Humour
     http://www.deutronium.de.vu || http://www.deutronium.tk
     "Olaf Baeyens" <olaf.baeyens...skyscan.be> schrieb im Newsbeitrag
     news:41b5c7a2$0$25047$ba620e4c...news.skynet.be...
     > I create a operator + in C#
     > public static HistogramBuffer operator+(HistogramBuffer
     > aHistogramBuffer1, HistogramBuffer aHistogramBuffer2) {
     > HistogramBuffer Tmp=new HistogramBuffer(aHistogramBuffer1);
     > for (int iX=0; iX<Tmp.NrOfValues; iX++) {
     > Tmp[iX]=Tmp[iX]+aHistogramBuffer2[iX];
     > }
     > return Tmp;
     > }
     > Now in C# I can do this:
     > HistogramBuffer Test1=new HistogramBuffer();
     > HistogramBuffer Test2=new HistogramBuffer();
     > Test2=Test2+Test1;
     > But if I do this In C++
     > HistogramBuffer __gc *Test1=__gc new HistogramBuffer();
     > HistogramBuffer __gc *Test2=__gc new HistogramBuffer();
     > Test2=Test2+Test1;
     > Then I get this error: "error C2845: '+' : cannot perform pointer
     arithmetic
     > on __gc pointer...."
     > Any idea how to fix this?
     > --
     > http://www.skyscan.be

     since Test1 and Test2 are not HistogramBuffers but pointers to a
     HistogramBuffer you have to write something like:

     Test2 = &((*Test2)+(*Test1));

     You dereference both Test2 and Test1, add them together and get the address
     of the result.

     But Iam not sure weather this will work :)

     cody | Mon, 31 Dec 2007 15:08:00 GMT |

  2. > since Test1 and Test2 are not HistogramBuffers but pointers to a
     > HistogramBuffer you have to write something like:
     > Test2 = &((*Test2)+(*Test1));
     > You dereference both Test2 and Test1, add them together and get the
     address
     > of the result.
     > But Iam not sure weather this will work :)
     It doesn't compile, I also tried many variations with typecasting.
     Anyway it looks very ugly if I have to do that this way.

     So for the C++ I added a Add()
     Like this:
     Test2->Add(Test1);

     While in C# I use
     Test2=Test2+Test1;

     Thanks for the reply. :-)

     --
     http://www.skyscan.be

     olafbaeyens | Mon, 31 Dec 2007 15:09:00 GMT |

  3. This works in VC 2005. Using * for __gc class instances made it almost
     semantically impossible to support this in the MC++ 1.x syntax.

     Ronald

     "Olaf Baeyens" <olaf.baeyens...skyscan.be> wrote in message
     news:41b6b741$0$25060$ba620e4c...news.skynet.be...
     >> since Test1 and Test2 are not HistogramBuffers but pointers to a
     >> HistogramBuffer you have to write something like:
     >>
     >> Test2 = &((*Test2)+(*Test1));
     >>
     >> You dereference both Test2 and Test1, add them together and get the
     > address
     >> of the result.
     >>
     >> But Iam not sure weather this will work :)
     >>
     > It doesn't compile, I also tried many variations with typecasting.
     > Anyway it looks very ugly if I have to do that this way.
     > So for the C++ I added a Add()
     > Like this:
     > Test2->Add(Test1);
     > While in C# I use
     > Test2=Test2+Test1;
     >
     > Thanks for the reply. :-)
     > --
     > http://www.skyscan.be

     ronaldlaeremansmsft | Mon, 31 Dec 2007 15:10:00 GMT |